CS403 Assignment No 2 Solution Fall 2023 – VU Assignment Solution – VU Fall Assignment Solution
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Assignment No. 2
Solution Fall 2023
CS403
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Solution
SQL Code:
CREATE Â TABLE Â COMPANY Â (
Comp_IDÂ VARCHAR(5) Â PRIMARY Â KEY, Comp_Name VARCHAR(50),
Comp_City  VARCHAR(50),
);  Comp_Ph  VARCHAR(15)               •
CREATE Â TABLE ITEM (Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1
Item_ID Â INT PRIMARY Â KEY,
enName VA.RCHAR(50),
Item_Unit  VARCHAR( 10),
Item_Quantity INT, CID VARCHAR(5),
FOREIGN Â KEY (CID) REFERENCES COMPANY(Comp_ID)
);
INSERT INTO COMPANY Â (Comp_ID, Comp_Name, Comp_City, Â Comp_Ph#) VALUES
(‘C00l ‘, ‘Toyota’, Â ‘Islamabad’, Â ‘051-321002’), (‘C002’, ‘Honda’, Â ‘Lahore’, Â ‘042-321002’), (‘C003’, ‘Suzuki’, Â ‘Peshawar’, Â ‘091-321002’),
(‘C004’, ‘MITSUBISHI’, Â ‘Quetta’, Â ‘081-321002’),
(‘C005′, ‘Nissan’, Â ‘Gilgit’, Â ‘092-321002’);
INSERT INTO ITEM (Item_ID, Item_Name, Item_Unit, Item_Quantity, Â CID) VALUES
(1, ‘Lights’, Â ‘PCs’, Â 50, Â ‘C00l’),
(2, ‘Bumper’, Â ‘PCs’, 20, Â ‘C002’), (3, ‘Seats’, Â ‘Set’, Â 10, Â ‘C003’),
(4, ‘Tires’, ‘Set’, Â 60, NULL),
(5, ‘Engine’, Â ‘PCs’, Â 5, NULL), (6, ‘Breaks’, Â ‘Set’, Â 14, ‘C005′);
- Theta Join on Company and Item tables having a condition ltem_Unit = PCs:
SELECT*
FROM COMPANY
JOIN ITEM ON COMPANY.Comp_ID = ITEM.CID WHERE ITEM.Item_Unit= ‘PCs’;
- i Equi Join on Company and Item tables:
SELECT*
FROM COMPANY
JOIN ITEM ON COMPANY.Comp_ID Â = ITEM.CID;
iii. Natural Join on Company and Item tables:
SELECT
FROM COMPANY
NATURAL Â JOIN iTEM
- iv. Semi Join on Company and Item tables:
SELECT*
FROM COMPANY
WHERE Â Comp_ID Â IN (SELECT DISTINCT Â CID FROM Â ITEM WHERE Â CID IS NOl
NULL);
- Theta Join on Company and Item tables having a condition ltem_Unit = PCs: Answer:
Relational Algebra Expression:
(COMPANY  l><l   ITEM ON Item_Unit = ‘PCs’
Comp_ID     Comp_Name     Comp_City    Comp_Ph     Item  IO    ltem  Name    Item  Unit     ltem_Quantity     CID C001            Toyota                 Islamabad       051-321002                 1     Lights            ~-     _I                       50   C001
C002           Honda                 Lahore            042-321002                2  Bumper
- ii. Equi Join on Company and Item tables: Answer:
Relational Algebra Expression:
(COMPANY Â l><JÂ Â Â ITEM ON COMPANY
Comp_ID | Comp_Name | Comp_City | Comp_Ph    Item  lD | ltem_Name | Item | Unit | Item_Quantity | CID | |
C001 | Toyota | Islamabad | 051-321002 | Lights | PCs | 50 | C001 | ||
C002           Honda                 Lahore           042-321002 —-2 Bumper           PCs                                     20  C002 |
|||||||||
C003 | Suzuki | Peshawar | 091 | M.junaid  Qazi | I
I |
Set | 10 | C003 | |
C005 | Nissan | Gilgit | 092- | 32T002z —6 | Breads | Set | 14 | C005 |
iii. Natural Join on Company and Item tables: Answer:
Relational Algebra Expression: COMPANY Â ITEM
- iv. Semi Join on Company and Item tables: Answer:
Relational Algebra Expression:
COMPANYÂ Â Â I><Â Â Â Â Â ITEM
- Comp_ID    Comp_Name    Comp_City     Comp_Ph
!         C001            Toyota —- Islamabad,   051-321002
!      C002           o MinaiOai_’  042-321002
! |
C003 | Suzuki | Peshawar | 091-321002 |
! |
C005 | Nissan | Gilgit | 092-321002 |
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